Question

Решите уравнение 5x²-12x+4=0

Answer 1

5x^2 - 12x  +4 = 0,        в = 12, а = 5, c = 4
D =  в^2 - 4*a*c;
D = 12^2 - 4*5*4 = 144 - 80 = 64; √64 = 8;
x1 = (-В + √D)/ 2a
x1 = (-(-12) + 8) / 2*5 = 20/10 = 2
x2 = (- B - √D)/2*a
x2 = (-(-12)- 8) /10 = 4/10 = 0.4
Ответ:x1 = 2 ;   x2 = 0.4