Предмет: Физика, автор: оаоаовл

при подъеме из колодца ведра воды массой 8 кг была совершена работа 640 Дж какова глубина колодца

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Автор ответа: solvo
0
Т.к. A=Fs, то s=A/F=A/(mg)=640/(8*10)=8 м.
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