Question

Объясните пожалуйста как решать
36√3tg$frac{ pi }{3}$sin$frac{ pi }{6}$
4sin$frac{ 17pi }{12}$*cos$frac{ 17pi }{12}$

Answer 1

Решение
1)  36√3 * tg(π/3) * sin(π/6) = 36√3 * √3 * (1/2) = 54
2)  4*sin(17π/12) * cos(17π/12) = 2sin[2*(17π/12)] = 2sin(17π/6) =
= 2*sin[(12π + 5π)/6] = 2*sin(2π + 5π/6) = 2*sin(5π/6) = 2*(1/2) = 1