Question

решите неравенство -8x-5(-3-10x)≥ -2x-3

Answer 1

$-8x-5(-3-10x) geq -2x-3 \ -8x+15+50x geq -2x-3 \ 42x+15 geq -2x-3 \ 42x+2x geq -3-15 \ 44x geq -18 \ x geq - frac{9}{22}$

Ответ:  $xin[- frac{9}{22} ;+infty)$

Answer 2

-8х-5(-3-10х)≥ -2х -3
-8х +15 +50х≥ -2х-3
42х+15≥-2х-3
42х+2х≥-3-15
44х≥-18
х≥-18/44
х≥- 9/22
х ∈ [-9/22;+∞)