Question

log 7776 по основанию √3

Answer 1

$log_{ sqrt{3} }7776 = log_{ 3^{ frac{1}{2} } } 7776=(1: frac{1}{2} )* log_{3} 7776=2* log_{3} 7776=$
$= log_{3} 7776 ^{2} =2* log_{3} (243*32) =2*( log_{3}243+ log_{3}32 )=$
$=2*(5+ log_{3}32 )=10+2* log_{3}32=10+ log_{3} 32 ^{2}$