Question

Сократите дробь:

во вложениях

Answer 1

а) (ay-az)/(by-ba)=(a(y-z))/(b(y-z))=a/b

б) (3+6c)/(2+4c)=(3(1+2c))/(2(1+2c))=3/2

в) (a^2-ab)/(ab-b^2)=(a(a-b))/(b(a-b))=a/b

г) (ax+2x)/(ay+2y)=(x(a+2))/(y(a+2))=x/y

Answer 2

а) (ay - az) / (by - bz) = (a(y - z)) / (b(y - z)) = a/b

 

б) (3 + 6c) / (2 + 4c) = (3(1 + 2c)) / (2(1 + 2c)) = 3/2 = 1,5

 

в) (a^2 - ab) / (ab - b^2) = (a(a - b)) / (b(a - b)) = a/b

 

г) (ax + 2x) / (ay + 2y) = (x(a + 2)) /( y(a + 2)) = x/y