Question

Решите уравнение: 2x^2+3x-2=0

Answer 1

$a=2 b=3 c=-2$
$2x^{2} +3x-2=0$
$D=b^{2}-4ac$
$x_{1} = frac{-b+ sqrt{D} }{2a} x_{2} = frac{-b- sqrt{D} }{2a}$
$D= 3^{2} -4*2*(-2)=9+16=25= 5^{2}$
$x_{1} = frac{-3+ sqrt{ 5^{2} } }{2*2} = frac{2}{4} = frac{1}{2}$
$x_{2} = frac{-3- sqrt{ 5^{2} } }{2*2} = frac{-8}{4} =-2$
Ответ: $x_{1} = frac{1}{2} x_{2} =-2$