Question

log 1/6 по основанию x=-3

Answer 1

$log_x( frac{1}{6})=-3 \ \ x^{-3} = frac{1}{6} \ \ frac{1}{x^3} = frac{1}{6} \ \ x^3=6 \ \ x= sqrt[3]{6}$

Answer 2

loga b = c togda, kogda b= aˇc
logx 1/6=-3 ⇔xˇ(-3)=1/6
1/x³=1/6 ⇒ x³=6    (p/q=r/s ⇔ p.s=q.r)
x=∛6
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