Question

2x^3-7x^2+2x+3=0
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Answer 1

$2x^3 - 7x^2 + 2x + 3=0\2x^3 - 2x^2 - 5x^2 + 5x - 3x + 3 = 0 \2x^2 * (x-1) - 5x * (x-1) - 3 * (x-1) = 0 \(x-1) * (2x^2 - 5x - 3) = 0 \x_1 = 1 \2x^2 - 5x - 3 = 0\ x_2 = 3\ x_3 = -0,5$