Предмет: Математика, автор: ника12310

найдите сумму первых пяти членов конечной геометрической прогрессии ,если b1 =6,
q= 3

Ответы

Автор ответа: Asila98

0

S5 =b1(1-q^n)/ (1-q)
S5 =6(1-3^5)/ (1-3)
S5= 6(1-243) / (-2)
S5 = 6*121= 726

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