Question

решите уравнение 36x^2-(3x-27)^2=0

Answer 1

$36 x^{2} - (3x-27)^{2} =0 \ 36 x^{2} -(9 x^{2} -162x+729)=0 \ 36 x^{2} -9 x^{2} +162x-729=0 \ 27 x^{2} +162x-729=0$
D = 162² - 4*27*(- 729) = 26244 + 78732 = 104976 = 324²
х₁ $=frac{-162+324}{2*27} = frac{162}{54} =3$
х₂$= frac{-162-324}{2*27} = - frac{486}{54} = - 9$
Ответ: 3 и - 9