Question

(x^2+2x)(-4-x^2)≥15(-4-x^2)
решите прошу пожалуйстаа

Answer 1

$(x^2+2x)(-4-x^2) geq 15(-4-x^2) \ -(x^2+2x)(x^2+4)+15(x^2+4) geq 0 \ (x^2+4)(-x^2-2x+15) geq 0 \ -x^2-2x+15=0; x^2+2x-15=0 \ D=4+60=64; x_{1,2} = frac{-2б8}{2} = -5; 3 \ x in [-5;3]$