Question

4
∫ (3-2x) dx
1
Помогите

Answer 1

$intlimits^4_1 {(3-2x)} , dx = -frac{1}{2}cdot frac{(3-2x)^2}{2} , |_1^4=-frac{1}{4}cdot ((3-8)^2-(3-2)^2)=\\=-frac{1}{4}cdot (25-1)=-6$