Предмет: Алгебра, автор: elinach12

5log 49 по основанию 25

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Автор ответа: Аноним

0

5*log₂₅49 = 5*2*log₂₅7 = 10*log₅7/log₅25= 10*log₅7/2= 5log₅7

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