Question

ОГРОМНАЯ ПРОСЬБА
arccos(cos 10)

Answer 1

$arccos(cos alpha )= alpha ; ,; ; esli; ; ; underline {underline {0 leq alpha leq pi }}\\10; radianapprox 573^circ =3cdot 180^circ +33^circ in 3; chetverti\\3pi textless 10, ; textless 4pi \\3pi -4pi textless 10-4pi textless 4pi -4pi \\-pi textless 10-4pi textless 0\\0 textless 4pi -10 textless pi ; ; Rightarrow ; ; arccos(cos10)=arccos(4pi -10)=4pi -10$