Question

Разложите на множетели:

а)16x^4-81

б)x^2-x-y^2-y

 

Answer 1

а)16x^4-81 = (4x^2-9)(4x^2+9) = (2x-3)(2x+3)(4x^2+9)

б)x^2-x-y^2-y = (x^2-y^2)-(x+y) = (х-у)(х+у) - 1(х+у) = (х-у-1)(х+у)

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Answer 2

$a)16x^4-81=(4x^2-9)(4x^2+9)=(2x-3)(2x+3)(4x^2+9)$

$b)x^2-x-y^2-y=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)$