Question

Помогите пожалуйста, 2С.55(а).

Answer 1

$(frac{3}{x-4} + frac{4x-6}{x^2-3x-4} + frac{2x}{x+1}) *frac{x}{2x-3} = \ \ = (frac{3}{x-4} + frac{4x-6}{x^2+x-4x-4} + frac{2x}{x+1}) *frac{x}{2x-3} = \ \ =(frac{3}{x-4} + frac{4x-6}{x(x+1)-4(x+1)} + frac{2x}{x+1}) *frac{x}{2x-3} = \ \ =(frac{3(x+1)}{(x-4)(x+1)} + frac{4x-6}{(x+1)(x-4)} + frac{2x(x-4)}{(x+1)(x-4)}) *frac{x}{2x-3} = \ \ = frac{3x+3+4x-6+2x^2-8x}{(x-4)(x+1)} *frac{x}{2x-3} = \ \ = frac{2x^2-x-3}{(x-4)(x+1)} *frac{x}{2x-3}=$

$= frac{2(x^2-0.5x-1.5)}{(x-4)(x+1)} *frac{x}{2(x-1.5)}= frac{2(x^2+x-1.5x-1.5)}{(x-4)(x+1)} *frac{x}{2(x-1.5)}= \ \ =frac{2(x(x+1)-1.5(x+1))}{(x-4)(x+1)} *frac{x}{2(x-1.5)}= frac{2x(x-1.5)(x+1)}{2(x-1.5)(x-4)(x+1) } = \ \ = frac{x}{x-4}$