Question

помагите решить 5(x-1)+7≤1-3(x+2)

Answer 1

5x-5+7≤1-3x-6

5x+3x≤1-6+5-7

8x≤-7

x≤-7/8

(-∞;-7/8]

Answer 2

$5(x-1)+7leq1-3(x+2) \ \ 5x-5+7leq1-3x-6 \ \ 5x+2leq-3x-5 \ \ 8xleq-7 \ \ xleq-frac{7}{8} \ \ xin(-infty; -frac{7}{8}]$