Question

2x^2+3x-2=0 x^1 x^2 найти корни

Answer 1

D=b^2-4ac=9-4*2*(-2)=25 √D=√25=5 x1= -b+√D/2a= -3+5/4=0,5 x2=-b-√D/2a=-3-5/4=-2