Question

Помогите вложение внутри !

Answer 1

№1

1)(t2+tx)+(11x+11t)=t(t+x)+11(t+x)=11t(x+t)

2)(8m2-4m)+(-2m3+m) = 4m(2m-1)-m(2m2-1)=3m(2m-1)

Answer 2

1)$a)t^2+tx+11x+11t=t(t+x)+11(x+t)=(x+t)(t+11)$
   $8m^2-2m^3-4+m=2m^2(4-m)-(4-m)=(4-m)(2m^2-1)$
2)$18k^2+7y-7ky-18k=18k(k-1)-7y(k-1)=(k-1)(18k-7y)</var>= =<var>(frac{1}{9}-1)(18*frac{1}{9}-7*frac{2}{7}=(-frac{8}{9})(2-2)=0$ 
3)$0.7*2.7-1.4*0.7+0.3*2.7-1.4*0.3=0.7(2.7-1.4)+</var><var>0.3(2.7-1.4)=(2.7-1.4)(0.7+0.3)=2.7-1.4=1.3$