Предмет: Алгебра, автор: ksyushkafenkop

Одновременно бросают два игральных кубика:

1) Какова вероятность того что на первом выпадет больше очков, чем на второй?

2) Какая сумма будет выпадать чаще 5 или 6?

3) Какое самое вероятное значение суммы выпавших очков?

Ответы

Автор ответа: Voxman
0

Во всех случаях исходов будет n = 6*6 = 36

 

1) Положительных исходов у нас m = frac{1}{2}(n - исходы, когда выпало одинаковое количество очков)

 

 

m = frac{36 - 6}{2} = 15

 

 

p = frac{m}{n} = frac{15}{36}

 

 

2) Сумму пять можно получить так: 1+4, 2+3, 3+2, 4+1. m_1 = 4

 

     Сумму шесть можно получить так: 1+5, 2+4, 3+3, 4+2, 5+1. m_2 = 5

 

    p_1 = frac{m_2}{n} = <var>frac{5}{36} </var>> p_2 = frac{4}{36}

 

     Выпадение суммы равной шести более вероятно, чем выпадение пяти.

 

3) Очевидно, что у нас имеется 36 возможных сумм, часть из которых совпадает. Меньше всего будет встречаться 2 (1+1) и 12 (6+6), чаще всего 7 (1+6, 2+5, 3+4, 4+3, 5+2, 6+1)

 

2 (1+1)

3 (1+2, 2+1)

4 (1+3, 2+2, 3+1)

5 (1+4, 2+3, 3+2, 4+1)

6 (1+5, 2+4, 3+3, 4+2, 5+1)

7 (1+6, 2+5, 3+4, 4+3, 5+2, 6+1)

8 (2+6, 3+5, 4+4, 5+3, 6+2)

9 (3+6, 4+5, 5+4, 6+3)

10 (4+6, 5+5, 6+4)

11 (5+6, 6+5)

12 (6+6)

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