Question

Помогите, пожалуйста

sin (7π/6)-cos(11π/6)+ctg(11π/4);

(sin(α-π)-cos(π/2-α))/cos(α-π)+sin(3π/2-α) ;

α-альфа

Answer 1

1)-1/2-sqrt(3)/2-1=(3-sqrt(3))/2

Answer 2

1) Sin (7π/6)-cos(11π/6)+ctg(11π/4)= sin(п/6)-cos(п/6)+ctg(-п/4)= -(1/2+v3/2)

2) (sin(α-π)-cos(π/2-α))/cos(α-π)+sin(3π/2-α)= sin(-(π-a))-cos(π/2-a)/ cos(-(π-a))+sin(3π/2-a)=0