Question

log7log3log2log2x=0
7, 3 и 2 - основания!

Answer 1

log7 (log3log2log2 x)=0
log3 (log2log2 x)=7^0=1
log2 (log2 x)=3^1=3
log2(x)=2³=8
x=2^8=256

Answer 2

Спасибо большое!)