Question

взять производную....

Answer 1

(x²-4)`=2x
(cosx/2+2sin3x)`=-1/2*sinx/2+6cos3x
(3/(x+4))`=-3/(x+4)²
(3x/(x+4))`=(3(x+4)-3x*1)/(x+4)²=(3x+12-3x)/(x+4)²=12/(x+4)²
$(x ^{3/4} -2x ^{3/2} +5)`=3/4*x ^{-1/4} -3x ^{1/2}$