Question

Найти производную функции

Answer 1

$y= frac{8x^2-32}{(x^2+4)^2} = frac{8(x^2-4)}{(x^2+4)^2} \ y'= 8*frac{2x(x^2+4)^2-(x^2-4)2(x^2+4)2x}{(x^2+4)^4} = frac{16x(x^2+4)[x^2+4-2(x^2-4)]}{(x^2+4)^4}$$=frac{16x(12-x^2)}{(x^2+4)^3}$