Предмет: Химия, автор: лизапилипенко

в растворе обьемом 200 мл с массовой долей хлороводорода 20% растворили 11,2л хлороводорода вычислите массовой долю хлороводорода в полученном растворе

Ответы

Автор ответа: goofy12

1) находим массу хлороводорода в расстаоре: 200/100=2•20=40 2) !!! Если децствительно добавили 11,2 хлороводорода то; (11,2+40)/(11,2+0,2(200мл в литрах)) *100 = 98,5 - это формула для подобных задач Надеюсь верно. Удачи!

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