Question

помогите со 2 и 3 заданием!!!!

Answer 1

№3
[(c²-10c+25)/(2C+4)]·[(4C+8)/(C²-25)] при с=7,5

=[(с-5)²/(2(c+2))]·[4(c+2)/((c-5)(c+5))] =2(c-5)/(c+5)=

 =2(7,5-5)/(7,5+5)=5/12,5=2/5=0,4

№1
(3/(y-2) - 3/(y+2))·(y²-4)/(y-4)=3{(y+2)-(y-2)}/(y²-4) ·{(y²-4)/(y-4)}=3·4/(y-4)=
=12/(y-4)