Предмет: Математика, автор: Пипип1

в треугольнике АВС угол А равен 54,угол В равен 63.Какая из сторон треугольника наибольшая?

Ответы

Автор ответа: Аноним
0
угол А=54,
угол В=63
Тогда угол С =180 -54-63 = 63
Напротив большей стороны лежит больший угол.
у нас два одинаковых угла по 63 градуса, значит две одинаковые стороны , треугольник равнобедренный АС=АВ  эти две стороны и есть самые  наибольшие.
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