Question

найдите все критические точки функции y=3-cos2x-4sinx

Answer 1

Решение
 y=3-cos2x-4sinx
y ` = 2sin2x - 4cosx
y ` = 0
2sin2x - 4cosx = 0
4sinx*cosx - 4cosx = 0
4cosx*(sinx - 1) = 0
1)  cosx = 0
x₁ = π/2 + πk, k ∈ Z
2)  sinx - 1 = 0
sinx = 1
x₂ = π/2 + 2πn, n ∈ Z