Question

найдите производные функции:

1. y=frac{4x+1}{3-2x}

2. y=(3-4x^{2})^{3}

3. y=3sin(3x-frac{pi}{3}

 

Answer 1

1. y=(4x+1)/(3-2x)

y'=[4(3-2x)-(-2)*(4x+1)]/(3-2x)²=24/(3-2x)²

2. y=(3-4x²)³

y'=3(3-4x²)²*(3-4x²)'=-24x*(3-4x²)²

3. y=3sin(3x-π/3)

y'=3cos(3x-π/3)*(3x-π/3)'=9cos(3x-π/3)