Question

Решите однородное тригонометрическое ур-ие!
3cos^2x+sinxcosx=2cos^2x

Answer 1

3cos²x+sinxcosx-2cos²x=0
cos²x+sinxcosx=0
cosx(cosx+sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx+sinx=0/cosx
1+tgx=0
tgx=-1⇒x=-π/4+πk,k∈z