Question

arcsin(-1) + arccos 1 + arctg(- корень_с_3/3) + arcctg(- корень_с_3)

Answer 1

$arcsin(-1)+arccos 1+arctg(-frac{sqrt3}{3})+arcctg(-sqrt3)=\\=-arcsin1+0-arctgfrac{sqrt3}{3}-arcctgsqrt3=\\=-frac{pi}{2}-frac{pi}{6}-frac{pi}{6}=frac{pi}{2}-frac{pi}{3}=frac{pi}{6}$