Question

$16^{1,5} - (0,25)^{-0,5} + 3,2^{0}$
Помогите

Answer 1

$16^{1.5}-0.25^{-0.5}+3.2^0=(4^2)^{1.5}- (frac{1}{4})^{-0.5}+1= \ 4^{2*1.5}-4^{0.5}+1=4^3-(2^2)^{0.5}+1=64-2^{2*0.5}+1=64-2^1+1= \ 64-2+1=63$