Question

Решите уравнение:
a) x^2+10x+22=0 b)x^2-110x+216=0

Answer 1

$1. x^2+10x+22=0\D=b^2-4ac\D=100-22*4=12\x_{1,2}= frac{-bpm sqrt{D} }{2a} \x_{1,2}= frac{-10pm sqrt{12} }{2}=-5pm sqrt{3}\ \ 2. x^2-110+216=0\ D=110^2-4*216=11236\x_1= frac{110- sqrt{11236} }{2} =frac{110- 106}{2} =2\x_1= frac{110+sqrt{11236} }{2} =frac{110+106}{2} =108$