Question

помогите решить тригонометрическое неравенство:3
cos2x(sin8x-1)<=0

Answer 1

1)cos2x≥0⇒-π/4+πn/2≤x≤π/4+πn/2,n∈z
sin8x≤1⇒x∈(∞;∞)
x∈[-π/4+πn/2;π/4+πn/2,n∈z]
2)cos2x≤0⇒π/4+πn/2≤x≤3π/4+πn,n∈z
sin8x≥1⇒x=π/16+2πn