Question

а) Log3(x+3)(x+5)+log3(x+3x+5)=4
б) log0.5^2 4x+log2 x^28 =8

Answer 1

$log _{3} (x+3)(x+5)+log_3 frac{x+3}{x+5} =4$
$(x+3)(x+5)* frac{x+3}{x+5} =3^4$
$(x+3)^2=81$
$x^2+6x+9-81=0$
$x^2+6x-72=0$
$D=324=18^2$
$x_{1} =6$
$x_{2} =-12$