Question

220(x+3)-210(x+2)-64(10)=0
определить значение X

Answer 1

$220_{x+3}-210_{x+2}-64=0 \ 2(x+3)^2+2(x+3)-2(x+2)^2-(x+2)=64 \ 2x^2+12x+18+2x+6-2x^2-8x-8-x-2=64 \ 5x=50to x=10 \ \ 220_{13}-210_{12}-64=0$