Question

Решите пожалуйста...

Answer 1

57√2sin405°=57√2sin(360°+45°)=57√2sin45°=57√2*(√2/2)=57

$frac{3cos alpha -15sin alpha +16}{5sin alpha -cos alpha +4} = tg alpha =0,2$

$frac{sin alpha }{cos alpha } =0,2 sin alpha =0,2*cos alpha$

$frac{3cos alpha -15*0,2*cos alpha +16}{5*0,2*cos alpha -cos alpha +4} = frac16}{4} =4$