Предмет: Геометрия, автор: Аноним

В треугольнике АВС угол А в 4 раза меньше угла В а угол С НА 90градусов меньше угла В . а) Найдите углы треугольника.б)СРАВНИТЕ стороны АВ и ВС

Ответы

Автор ответа: vivalaviva12

1) угол B = x

Тогда угод C = x-90

угоk A = x/4

x + x/4 + (x-90) = 180

x+ x/4 + x = 270 /4

4x + x + 4x = 1080

9x = 1080

x = 120

Тогда угол A= 120/4 = 30

угол C = 120-90 = 30

2) AB = BC и треугольник р/б углы при основании равны 30 градусов.

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