Question

2х^2+tx+8=0
помогите пжж

Answer 1

$2 x^{2} +tx+8=0 D= t^{2} -64 x_{1} = frac{-1+ sqrt{ t^{2} -64 } }{4} x_{2} = frac{-1- sqrt{ t^{2} -64 } }{4}$