Question

Задание во вложении, 8 номер

Answer 1

$x^6-64=(x^3)^2-8^2=(x^3-8)(x^3+8)=$

$=(x-2)(x^2+2x+4)(x+2)(x^2-2x+4)$ 

 

 $x^6-64=(x^2)^3-4^3=(x^2-4)(x^4+4x^2+16)=$

$=(x-2)(x+2)(x^4+4x^2+16)$ 

Answer 2

х⁶-64=(x²)³-4³

х⁶-64=x⁸/x²-2⁶

х⁶-64=√x¹²-√4096