Question

ОГЭ 21 номер !!!!!!!!!!!!

Answer 1

$left { {{frac{2-x}{2+(3-x)^2} textgreater 0} atop {6-9x leq 31-4x}} right. ; left { {frac{-(x-2)}{x^2-6x+11} textgreater 0} atop {5x geq -22}} right. ; left { {{-(x-2) textgreater 0} atop {x geq -frac{22}{5}}} right. ; left { {{x textless 2} atop {x geq -4,4}} right. \\xin [, -4,4; ;; 2)\\P.S.; ; x^2-6x+11=0; ; to ; ; D=36-44=-8 textless 0; ; to \\net; dejstvitelnux; kornej; ; i; ; x^2-6x+11 textgreater 0; pri; xin (-infty ,+infty )$