Question

Решите систему
X2+4y2=25
3x2+12y2=25x

Answer 1

$left { {{x^2+4y^2=25|cdot 3} atop {3x^2+12y^2=25x}} right. ; left { {{3x^2+12y^2=75} atop {3x^2+12y^2=25x}} right. ; ominus; left { {{75-25x=0} atop {x^2+4y^2=25}} right. ; left { {{25x=75} atop {x^2+4y^2=25}} right. \\ left { {{x=3} atop {3^2+4y^2=25}} right. ; left { {{x=3} atop {4y^2=16}} right. ; left { {{x=3} atop {y^2=4}} right. ; left { {{x=3} atop {y=pm 2}} right. \\Otvet:; ; (3,-2); ,; (3,-2).$