Предмет: Алгебра, автор: dmitryryzhykov

Помогите пожалуйста решить: представьте в виде суммы или разности выражения 1)-2sin25°sin15°; 2) 2sin27°cos9°

Ответы

Автор ответа: sedinalana

-2sin25sin15=-2*1/2(cos(25-15)-cos(25+15))=-(cos10-cos40)=
=-cos10+cos40

2sin27cos9=2*1/2(sin(27-9)+sin(27+9)=sin18+sin36

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