Question

решите уравнение
3x^2-4x-1=0

Answer 1

$3x^2-4x-1=0$

$D=(-4)^2-4*3*-1=16+12=28$

$sqrt{D} = sqrt{28} = sqrt{7*4} = 2 sqrt{7}$

$x_{1} = frac{4+2 sqrt{7} }{2*3} = frac{2+ sqrt{7} }{3}$

$x_{2} = frac{4-2 sqrt{7} }{2*3} = frac{2- sqrt{7} }{3}$