Question

1) интеграл 2 по 1 (2x+3x^2)dx 2)byntuhfk 0 по -1 (9x^2-4x)dx

Answer 1

Integral from 1 to 2 (2x+3x^2) = x^2+x^3 |(двойная подстановка) = -10.
Integral from 0 to -1 (9x^2-4x) = 3x^3-2x^2|(двойная подстановка) = -5