Question

физика, 9 класс
помогите пожалуйста, вообще в физике не соображаю

Answer 1

1.
$^{251}_{98}Cf = ^{211}_{85}At + k*^{4}_{2}He + m*^{0}_{-1}e \ \ left { {{251=211+4k} atop {98=85+2k-m}} right. \ left { {{k=10} atop {m=7}} right \ \ ^{251}_{98}Cf = ^{211}_{85}At + 10^{4}_{2}He + 7^{0}_{-1}e$
Т. е. происходит 10 α-распадов и 7 β-распадов.

$^{254}_{99}Es = ^{222}_{87}Fr + k*^{4}_{2}He + m*^{0}_{-1}e \ \ left { {{254=222+4k} atop {99=87+2k-m}} right. \ left { {{k=8} atop {m=4}} right \ \^{254}_{99}Es = ^{222}_{87}Fr + 8^{4}_{2}He + 4^{0}_{-1}e$
Т. е. происходит 8 α-распадов и 4 β-распада.
2.
$^{16}_{8}O + ^{1}_{0}n = ^{14}_{7}N + ^{k}_{m}E \ \ left { {{16+1=14+k} atop {8+0=7+m}} right. \ left { {{k=3} atop {m=1}} right \ \^{3}_{1}E = ^{3}_{1}H \ \ ^{16}_{8}O + ^{1}_{0}n = ^{14}_{7}N +^{3}_{1}H$

$^{15}_{7}N + ^{4}_{2} alpha = ^{12}_{6}C + ^{k}_{m}E \ \ left { {{15+4=12+k} atop {7+2=6+m}} right. \ left { {{k=7} atop {m=3}} right \ \^{7}_{3}E = ^{7}_{3}Li \ \ ^{15}_{7}N + ^{4}_{2} alpha = ^{12}_{6}C + ^{7}_{3}Li$
3.
$^{2}_{1}H + ^{3}_{1}H= ^{4}_{2}He + ^{k}_{m}E \ \ left { {{2+3=4+k} atop {1+1=2+m}} right. \ left { {{k=1} atop {m=0}} right \ \^{1}_{0}E = ^{1}_{0}n \ \^{2}_{1}H + ^{3}_{1}H= ^{4}_{2}He + ^{1}_{0}n \ \ \^{6}_{3}Li + ^{1}_{1}H= ^{4}_{2}He + ^{k}_{m}E \ \ left { {{6+1=4+k} atop {3+1=2+m}} right. \ left { {{k=3} atop {m=2}} right \ \^{3}_{2}E = ^{3}_{2}He \ \^{6}_{3}Li + ^{1}_{1}H= ^{4}_{2}He +^{3}_{2}He$