Question

решите уравнение
(2x-5)^2-(2x-3)^2=0

Answer 1

$(2x-5)^{2} - (2x-3)^{2} = 0 \ 4 x^{2} -20x+25-(4 x^{2} -12x+9)=0 \ 4 x^{2} -20x+25-4 x^{2} +12x-9=0 \ -20x+12x+25-9=0 \ -8x+16=0 \ -8x=-16 \ 8x=16 \ x=2$