Question

решите пожалйста,кто может
х³+3х²-4х-12=0

Answer 1

х³+3х²-4х-12=0

x^2(x+3) - 4(x+3)=0

(x^2-4)(x+3)=0

(x-2)(x+2)(x-3)=0

x=2; x=-2; x=3

Answer 2

(x3+3x)-(4x+12)=0

x2(x+3)-4(x+3)=0

(x2-4)(x+3)=0

x2-4=0 / x+3=0

x=-2;2;-3