Question

(a^5)^-2/5*(b^-2/3)^-3

Answer 1

$(a^{5})^{-2/5}*(b^{-2/3})^{-3} = a^{5*(-2/5)}*b^{(-2/3)*(-3)} = a^{-2}b^{2} = frac{b^{2}}{a^{2}}.$

Answer 2

$(a^5)^{-frac{2}{5}}(b^{-frac{2}{3}})^{-3}=a^{5*frac{-2}{5}}b^{-frac{2}{3}*(-3)}=a^{-2}b^2=frac{1}{a^2}*b^2=frac{b^2}{a^2}$